Lesson 3.2 · 25 min
Constructions
Constructing angles of 60°, 30°, 90° and 45°, and perpendiculars from a point on — or off — a line.
In this lesson you will learn to…
- Construct a angle and bisect it to get
- Construct a perpendicular at a point on a line, and bisect it to get
- Construct the perpendicular from a point to a line
- Combine constructions to make other angles such as and
Why this matters
Before protractors and computers, builders set out right angles for walls and foundations with pegs and string using exactly these constructions. They are still the most accurate way to draw angles by hand — a compass does not have the small reading errors of a protractor.
The toolkit
Every construction in this lesson is built from two moves:
- Equal arcs. Two points the same distance from a third lie on a circle round it.
- Crossing arcs. Where two arcs of equal radius from A and B cross, the point is the same distance from A as from B.
| Construction | Result |
|---|---|
| Equilateral-triangle arcs | |
| Perpendicular at a point on a line | |
| Perpendicular bisector of a line segment | through the midpoint |
| Perpendicular from a point to a line | from a point off the line |
| Angle bisector | half of any angle |
Making other angles
Once you can make and and halve any angle, many more follow:
- : bisect . : bisect .
- : bisect . : bisect .
- : two angles side by side, or on a straight line.
- : , or .
Constructing a triangle from angles
To construct a triangle with a 6 cm base and base angles of and : draw the 6 cm base (measuring this is allowed — it is given), construct at one end and at the other, and extend the arms until they meet.
Neat work matters. Use a sharp pencil, make the arcs long enough to cross clearly, and never rub them out.
Key rules and formulas
60° comes from an equilateral triangle
Keep the compasses the same width throughout. The three points X, A and Y are all one radius apart, so triangle XAY is equilateral and angle YXA is .Bisecting halves any angle
Arc from the vertex to cut both arms, then equal arcs from those two points. The line from the vertex through the crossing splits the angle exactly in half.90° from a perpendicular
Arcs from X cut the line at A and B. Wider arcs from A and B cross at P and Q. PQ is perpendicular to the line.Building other angles
Halve, add and subtract: ; ; and .
Worked examples
Constructing 60° and 30°
Try it yourself first, then reveal the solution one step at a time.
The perpendicular from a point to a line
Try it yourself first, then reveal the solution one step at a time.
Practice: constructions
10 questions
Question 1 of 10Put in order Put the steps for constructing a angle at X in order.Put these in the right order. Drag them, or use the arrow buttons.
- With centre X, draw an arc that cuts the line at A
- Keeping the same width, draw an arc with centre A that cuts the first arc at Y
- Join X to Y
- Draw a line and mark the point X on it
Question 2 of 10Multiple choice Why does the construction work?Question 3 of 10Match the pairs Match each angle to the quickest way to construct it.Pick an answer, then choose the row it belongs to. You can also drag it.
Question 4 of 10True or falseChallenge You can construct an angle of by bisecting angles, starting from or .Question 5 of 10Put in order Put the steps for constructing a perpendicular at the point X on a line in order.Put these in the right order. Drag them, or use the arrow buttons.
- Join P to Q
- Open the compasses wider
- Draw arcs from A and from B that cross above and below the line at P and Q
- With centre X, draw arcs that cut the line at A and B
Question 6 of 10Multiple choice To construct the perpendicular from a point X above a line, what is the first step?Question 7 of 10Step by step Plan a construction one step at a time.You draw AB = 8 cm, construct a angle at A, and mark C on the new line so that AC = 6 cm. Then you join B to C.- What kind of triangle is ABC?
Question 8 of 10Choose all that apply A triangle has a 6 cm base with angles of and at its ends. Which constructions do you need?Select every correct answer — there may be more than one.
Question 9 of 10Type the answer You construct a angle on a straight line. What is the angle on the other side of the arm, on the same straight line?°Question 10 of 10Flashcards Flip through the constructions. Picture each one before you turn the card.Card 1 of 5
Tap the card to flip it