Lesson 16.5 · 60 min
Non-linear Simultaneous Equations
Where a straight line meets a parabola, a circle or another curve: forming one quadratic equation, using the discriminant to count — or control — the points of intersection, and solving to find them, with the formula when it will not factorise.
In this lesson you will learn to…
- Form a single quadratic equation by setting a line equal to a curve, or by substituting
- Use the discriminant to decide whether there are 2, 1 or 0 points of intersection
- Solve by factorising and substitute back to find both coordinates
- Solve a line and a circle simultaneously, expanding brackets carefully
- Recognise when a line is a tangent to a curve
- Stretch: use the quadratic formula when the equation does not factorise, giving exact (surd) or 3 s.f. answers
- Stretch: find the values of for which a line meets, touches or misses a curve
- Stretch: solve with other curves, such as or
Why we get a quadratic
Two linear equations make two straight lines, which cross at most once. Now one of the equations is a curve — a parabola or a circle . The points where the line meets the curve satisfy both equations, and combining them gives a quadratic — which is why there can be two answers.
Move the line across the parabola
- Curve
- y = x² − 4
- Line
- y = x + 2
- Combined equation
- x² − x − 6 = 0
- Discriminant
- (-1)² − 4(1)(-6) = 25
- So
- b² − 4ac > 0: two points of intersection
- Points
- (-2, 0) and (3, 5)
This is and — question 1 from class. Change the line and watch the discriminant. Can you make the line just touch the curve? (Try a gradient of 2 with , or a gradient of 0 with .) Can you make it miss completely?
The discriminant tells you how many
Once you have the combined equation , the discriminant predicts what will happen before you solve anything:
| Points of intersection | Picture | |
|---|---|---|
| positive | 2 | the line cuts through the curve |
| zero | 1 | the line just touches — a tangent |
| negative | 0 | the line misses the curve |
Solving: a line and a parabola
When both equations start with , set them equal. Collect everything on one side, check the discriminant, factorise, and then substitute back to find each .
A line and a circle
A circle with centre and radius has equation . Make the subject of the linear equation, substitute it into the circle, and expand carefully — the squared bracket is where most marks are lost.
Stretch: beyond the class questions
The class questions all factorise neatly. Exam questions often do not — and they combine this topic with the discriminant work you already know.
When it will not factorise
If is positive but not a square number, there are still two points — they just are not whole numbers. Use the quadratic formula, and give the answer exactly (with surds) or to 3 significant figures, as the question asks.
Questions about
Instead of a fixed line, you may be given a family of lines such as and asked which values of make it meet, touch or miss the curve. Keep in the combined equation and turn the discriminant into an inequality — exactly the “range of values of ” method from your discriminant work.
Other curves
Nothing in the method depends on the curve being a parabola or a circle. With or , substitute the line, multiply out, and you get a quadratic again.
Key rules and formulas
The method
1. Make the subject of the linear equation (if it is not already). 2. Set the two equations equal, or substitute, to get one equation in . 3. Rearrange to . 4. Solve — usually by factorising. 5. Substitute each back into the linear equation to find . 6. Write the answers as coordinates.The discriminant counts the points
Work it out from the combined equation before you try to factorise. If it is negative, there is nothing to find. If it is a perfect square (1, 4, 9, 16, 25, …) the equation will factorise.Lines and circles
For , substitute the line into the circle. Expand the squared bracket in full: .Give pairs of values
Each has its own . Write them as coordinates, and , not as four loose numbers.Stretch: when it will not factorise
If is positive but not a square number, use the formula. Simplify the surd for exact answers (), or round to 3 s.f. only at the very end.Stretch: questions about
Form the combined equation with in it, then write the discriminant as an inequality and solve for : meets at two points → ; tangent → ; misses → .
Worked examples
A line and a parabola
Try it yourself first, then reveal the solution one step at a time.
When is not 1
Try it yourself first, then reveal the solution one step at a time.
A line and a circle
Try it yourself first, then reveal the solution one step at a time.
A tangent
Try it yourself first, then reveal the solution one step at a time.
Stretch: when does a line miss a circle?
Try it yourself first, then reveal the solution one step at a time.
Practice: non-linear simultaneous equations
20 questions
Question 1 of 20Type the answer The line meets the curve . Form the combined equation and find its discriminant.Question 2 of 20Multiple choice How many points of intersection do and have?Question 3 of 20Multiple choice How many points of intersection do and have?Question 4 of 20Fill the gaps Solve and simultaneously.Points: ( , ) and ( , )
Question 5 of 20Fill the gaps Solve and simultaneously.Points: ( , ) and ( , )
Question 6 of 20Fill the gapsChallenge Solve and simultaneously.Points: ( , ) and ( , )
Question 7 of 20Fill the gaps Solve and simultaneously.Points: ( , ) and ( , )
Question 8 of 20Step by stepChallenge A line that touches a circle.The line meets the circle .- Make the subject of the line and substitute. Which equation do you get after simplifying?
Question 9 of 20Step by step A circle with an easy-to-miss bracket.Solve and simultaneously.- Expand .
Question 10 of 20Type the answerChallenge The line is a tangent to the curve . Find .Question 11 of 20Explore and match Move the line until it is a tangent to (exactly one point of intersection).Move the controls until you match the question, then press Check.
- Curve
- y = x² − 4
- Line
- y = x + 2
- Combined equation
- x² − x − 6 = 0
- Discriminant
- (-1)² − 4(1)(-6) = 25
- So
- b² − 4ac > 0: two points of intersection
- Points
- (-2, 0) and (3, 5)
- Aim for
- 1 point of intersection
Question 12 of 20Step by stepChallenge In context.A ball follows the path . A straight ramp follows . Find where the ball's path meets the ramp.- Which equation do you get?
Question 13 of 20Multiple choiceChallenge Stretch. Solve and simultaneously. What are the -coordinates, exactly?Question 14 of 20Fill the gapsChallenge Stretch. Solve and simultaneously. Give your answers correct to 3 significant figures, the point with the smaller first.( , ) and ( , )
Question 15 of 20Fill the gapsChallenge Stretch. The line meets the curve at two points. Find the range of values of .Question 16 of 20Fill the gapsChallenge Stretch. The line is a tangent to the curve . Find the two possible values of .or
Question 17 of 20Fill the gapsChallenge Stretch. For which values of does the line miss the circle ?or
Question 18 of 20Fill the gapsChallenge Stretch. Solve and simultaneously. Give the point with the smaller first.( , ) and ( , )
Question 19 of 20Step by stepChallenge Stretch. Substituting for instead of .Solve and simultaneously.- Which is easier to make the subject of ?
Question 20 of 20Put in order Stretch. Put the lines of this proof in order: Show that the line does not meet the curve .Put these in the right order. Drag them, or use the arrow buttons.
- , so there are no real solutions: the line does not meet the curve.